-n^2+91n+92=0

Solution for -n^2+91n+92=0 equation:

-n^2+91n+92=0

We add all the numbers together, and all the variables

-1n^2+91n+92=0

a = -1; b = 91; c = +92;
Δ = b2-4ac
Δ = 912-4·(-1)·92
Δ = 8649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8649}=93$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(91)-93}{2*-1}=\frac{-184}{-2}
=+92
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(91)+93}{2*-1}=\frac{2}{-2}
=-1
$